What is expand ((x-2)(x^2+2x+4))/(x^3) ?

The solution to expand ((x-2)(x^2+2x+4))/(x^3) is 1-8/(x^3)

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expand ((x-2)(x^2+2x+4))/(x^3)

expand

\frac{( x - 2 ) ( x ^{2} + 2 x + 4 )}{x ^{3}}

1 - \frac{8}{x ^{3}}

Solution steps

\frac{( x - 2 ) ( x ^{2} + 2 x + 4 )}{x ^{3}}

Expand

(x - 2) (x^{2} + 2 x + 4) : x^{3} - 8

= \frac{x ^{3} - 8}{x ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} - 8}{x ^{3}} = \frac{x ^{3}}{x ^{3}} - \frac{8}{x ^{3}}

= \frac{x ^{3}}{x ^{3}} - \frac{8}{x ^{3}}

Apply rule

\frac{a}{a} = 1

\frac{x ^{3}}{x ^{3}} = 1

= 1 - \frac{8}{x ^{3}}

(\frac{x ^{4}}{2} + \frac{4}{3 x ^{2}})^{12}

(2 x + 3 y - 7) d x + (- 3 x - 2 y - 4) d y

\frac{1}{4 s t ( 1 + s ) ( 1 + t )}

100 ((0.75 \cdot 129218, 71) + (0, 25 \cdot 60301, 99))

(2 x + 3 + x^{2}) (2 x + 3 = x^{2})

What is expand ((x-2)(x^2+2x+4))/(x^3) ?
The solution to expand ((x-2)(x^2+2x+4))/(x^3) is 1-8/(x^3)