What is (xy}{2b^2}x\frac{4b)/1 ?

The solution to (xy}{2b^2}x\frac{4b)/1 is (2x^2y)/b

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simplify (xy}{2b^2}x\frac{4b)/1

simplify

\frac{x y}{2 b ^{2}} x \frac{4 b}{1}

\frac{2 x ^{2} y}{b}

Solution steps

\frac{x y}{2 b ^{2}} x \frac{4 b}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{4 b}{1} = 4 b

= \frac{x y}{2 b ^{2}} x \cdot 4 b

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x y x \cdot 4 b}{2 b ^{2}}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{x ^{2} y \cdot 4 b}{2 b ^{2}}

Factor the number:

4 = 2 \cdot 2

= \frac{x ^{2} y \cdot 2 \cdot 2 b}{2 b ^{2}}

Cancel the common factor:

2

= \frac{x ^{2} y \cdot 2 b}{b ^{2}}

Simplify

\frac{b}{b ^{2}} : \frac{1}{b}

= \frac{x ^{2} y \cdot 2}{b}

= \frac{2 x ^{2} y}{b}

200 - 32

73 < \frac{n}{2} + 76

\frac{3}{8} x + \frac{1}{2} < \frac{1}{4} x + 2

4 v^{2} + 3 = - 8 v

x^{8} - 625

What is (xy}{2b^2}x\frac{4b)/1 ?
The solution to (xy}{2b^2}x\frac{4b)/1 is (2x^2y)/b