What is (\partial)/(\partial v)((x)(-v+2u+2)) ?

The answer to (\partial)/(\partial v)((x)(-v+2u+2)) is -x

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(\partial)/(\partial v)((x)(-v+2u+2))

\frac{\partial}{\partial v} ((x) (- v + 2 u + 2))

- x

Solution steps

\frac{\partial}{\partial v} ((x) (- v + 2 u + 2))

Treat

x, u

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial v} (- v + 2 u + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (- \frac{\partial}{\partial v} (v) + \frac{\partial}{\partial v} (2 u) + \frac{\partial}{\partial v} (2))

\frac{\partial}{\partial v} (v) = 1

\frac{\partial}{\partial v} (2 u) = 0

\frac{\partial}{\partial v} (2) = 0

= x (- 1 + 0 + 0)

Simplify

= - x

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What is (\partial)/(\partial v)((x)(-v+2u+2)) ?
The answer to (\partial)/(\partial v)((x)(-v+2u+2)) is -x