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Popular >

expand ((3x-1)^2)/9

Solution

expand

\frac{( 3 x - 1 ) ^{2}}{9}

Solution

x^{2} - \frac{2 x}{3} + \frac{1}{9}

Solution steps

\frac{( 3 x - 1 ) ^{2}}{9}

(3 x - 1)^{2} = 9 x^{2} - 6 x + 1

= \frac{9 x ^{2} - 6 x + 1}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 6 x + 1}{9} = \frac{9 x ^{2}}{9} - \frac{6 x}{9} + \frac{1}{9}

= \frac{9 x ^{2}}{9} - \frac{6 x}{9} + \frac{1}{9}

Divide the numbers:

\frac{9}{9} = 1

= x^{2} - \frac{6 x}{9} + \frac{1}{9}

Cancel

\frac{6 x}{9} : \frac{2 x}{3}

= x^{2} - \frac{2 x}{3} + \frac{1}{9}

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Frequently Asked Questions (FAQ)

What is expand ((3x-1)^2)/9 ?
The solution to expand ((3x-1)^2)/9 is x^2-(2x)/3+1/9