What is expand (2-2x)e^{2x-x^2-4y-y^2=0} ?

The solution to expand (2-2x)e^{2x-x^2-4y-y^2=0} is 2e^{2x-x^2-4y-0=y^2}-2e^{2x-x^2-4y-0=y^2}x

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expand (2-2x)e^{2x-x^2-4y-y^2=0}

expand

(2 - 2 x) e^{2 x - x^{2} - 4 y - y^{2} = 0}

2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} - 2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} x

Solution steps

(2 - 2 x) e^{2 x - x^{2} - 4 y - y^{2} = 0}

= e^{2 x - x^{2} - 4 y - 0 = y^{2}} (2 - 2 x)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 x - x^{2} - 4 y - y^{2} = 0}, b = 2, c = 2 x

= e^{2 x - x^{2} - 4 y - y^{2} = 0} \cdot 2 - e^{2 x - x^{2} - 4 y - y^{2} = 0} \cdot 2 x

= 2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} - 2 e^{2 x - x^{2} - 4 y - 0 = y^{2}} x

(x + 3 y)^{5}

, (\frac{1}{44 + 210 j} + \frac{1}{50 + 80 j})

(2 t cos (5 t) + 3 t sinh (t)) (s)

(x^{2} - x) e^{2 x}

4 (2 w - \frac{315}{w ^{2}})

What is expand (2-2x)e^{2x-x^2-4y-y^2=0} ?
The solution to expand (2-2x)e^{2x-x^2-4y-y^2=0} is 2e^{2x-x^2-4y-0=y^2}-2e^{2x-x^2-4y-0=y^2}x