What is expand 2t[\H(t)-\H(t-1)]+2\H(t-1) ?

The solution to expand 2t[\H(t)-\H(t-1)]+2\H(t-1) is 2t\H(t)-2t\H(t-1)+2\H(t-1)

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expand 2t[\H(t)-\H(t-1)]+2\H(t-1)

expand

2 t [H (t) - H (t - 1)] + 2 H (t - 1)

2 t H (t) - 2 t H (t - 1) + 2 H (t - 1)

Solution steps

2 t (H (t) - H (t - 1)) + 2 H (t - 1)

Expand

2 t (H (t) - H (t - 1)) : 2 t H (t) - 2 t H (t - 1)

= 2 t H (t) - 2 t H (t - 1) + 2 H (t - 1)

\frac{x}{( x + 6 ) ( x + 9 )}

3 + 2 sin (3) (x + 1)

\frac{( 50 x ^{(2)} - 4 )}{( ( x + 5 ) ( x - 8 ) )}

u (1 - u)

\frac{9 x ^{3}}{( 1 + 3 x ) ^{2}}

What is expand 2t[\H(t)-\H(t-1)]+2\H(t-1) ?
The solution to expand 2t[\H(t)-\H(t-1)]+2\H(t-1) is 2t\H(t)-2t\H(t-1)+2\H(t-1)