What is expand (2^{-x-1}(x+2))/(x(x+1)) ?

The solution to expand (2^{-x-1}(x+2))/(x(x+1)) is (2^{-x-1}x+2^{-x})/(x^2+x)

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expand (2^{-x-1}(x+2))/(x(x+1))

expand

\frac{2 ^{- x - 1} ( x + 2 )}{x ( x + 1 )}

\frac{2 ^{- x - 1} x + 2 ^{- x}}{x ^{2} + x}

Solution steps

\frac{2 ^{- x - 1} ( x + 2 )}{x ( x + 1 )}

Expand

x (x + 1) : x^{2} + x

= \frac{2 ^{- x - 1} ( x + 2 )}{x ^{2} + x}

Expand

2^{- x - 1} (x + 2) : 2^{- x - 1} x + 2^{- x}

= \frac{2 ^{- x - 1} x + 2 ^{- x}}{x ^{2} + x}

150 [4 (0.005) + \frac{1}{2} sin ((8) 0.005)]

- 4 (x - 2) e^{8 x}

1 - \frac{1}{x ^{2.8 - 1}}

n^{\frac{1}{2}} (n^{\frac{3}{2}} + n + 5)

lo g_{7} (x) (5 y (3 y + 4))

What is expand (2^{-x-1}(x+2))/(x(x+1)) ?
The solution to expand (2^{-x-1}(x+2))/(x(x+1)) is (2^{-x-1}x+2^{-x})/(x^2+x)