What is expand ((x+1)(x^5-4x^4+4x^3-6x-2))/x ?

The solution to expand ((x+1)(x^5-4x^4+4x^3-6x-2))/x is x^5-3x^4+4x^2-6x-8-2/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x+1)(x^5-4x^4+4x^3-6x-2))/x

expand

\frac{( x + 1 ) ( x ^{5} - 4 x ^{4} + 4 x ^{3} - 6 x - 2 )}{x}

x^{5} - 3 x^{4} + 4 x^{2} - 6 x - 8 - \frac{2}{x}

Solution steps

\frac{( x + 1 ) ( x ^{5} - 4 x ^{4} + 4 x ^{3} - 6 x - 2 )}{x}

Expand

(x + 1) (x^{5} - 4 x^{4} + 4 x^{3} - 6 x - 2) : x^{6} - 3 x^{5} + 4 x^{3} - 6 x^{2} - 8 x - 2

= \frac{x ^{6} - 3 x ^{5} + 4 x ^{3} - 6 x ^{2} - 8 x - 2}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{6} - 3 x ^{5} + 4 x ^{3} - 6 x ^{2} - 8 x - 2}{x} = \frac{x ^{6}}{x} - \frac{3 x ^{5}}{x} + \frac{4 x ^{3}}{x} - \frac{6 x ^{2}}{x} - \frac{8 x}{x} - \frac{2}{x}

= \frac{x ^{6}}{x} - \frac{3 x ^{5}}{x} + \frac{4 x ^{3}}{x} - \frac{6 x ^{2}}{x} - \frac{8 x}{x} - \frac{2}{x}

\frac{x ^{6}}{x} = x^{5}

\frac{3 x ^{5}}{x} = 3 x^{4}

\frac{4 x ^{3}}{x} = 4 x^{2}

\frac{6 x ^{2}}{x} = 6 x

\frac{8 x}{x} = 8

= x^{5} - 3 x^{4} + 4 x^{2} - 6 x - 8 - \frac{2}{x}

(u - v)^{2}

\frac{2 s - 2}{s ^{2} ( s + 1 ) ^{3}}

\frac{1}{( s + 1 ) ( 2 s ^{3} + 3 s ^{2} - 3 s - 2 )}

x^{2} (ln (x + 10) - 1)

1.60799 \cdot 1 0^{13}

What is expand ((x+1)(x^5-4x^4+4x^3-6x-2))/x ?
The solution to expand ((x+1)(x^5-4x^4+4x^3-6x-2))/x is x^5-3x^4+4x^2-6x-8-2/x