What is expand 2x^{1/5}y(4x^{2/5}y^{1/2}-10x^{1/3}) ?

The solution to expand 2x^{1/5}y(4x^{2/5}y^{1/2}-10x^{1/3}) is 8x^{3/5}y^{3/2}-20x^{8/15}y

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expand 2x^{1/5}y(4x^{2/5}y^{1/2}-10x^{1/3})

expand

2 x^{\frac{1}{5}} y (4 x^{\frac{2}{5}} y^{\frac{1}{2}} - 10 x^{\frac{1}{3}})

8 x^{\frac{3}{5}} y^{\frac{3}{2}} - 20 x^{\frac{8}{15}} y

Solution steps

2 x^{\frac{1}{5}} y (4 x^{\frac{2}{5}} y^{\frac{1}{2}} - 10 x^{\frac{1}{3}})

Apply the distributive law:

a (b - c) = ab - a c

2 x^{\frac{1}{5}} y (4 x^{\frac{2}{5}} y^{\frac{1}{2}} - 10 x^{\frac{1}{3}}) = 2 x^{\frac{1}{5}} y \cdot 4 x^{\frac{2}{5}} y^{\frac{1}{2}} - 2 x^{\frac{1}{5}} y \cdot 10 x^{\frac{1}{3}}

= 2 x^{\frac{1}{5}} y \cdot 4 x^{\frac{2}{5}} y^{\frac{1}{2}} - 2 x^{\frac{1}{5}} y \cdot 10 x^{\frac{1}{3}}

2 x^{\frac{1}{5}} y \cdot 4 x^{\frac{2}{5}} y^{\frac{1}{2}} = 8 x^{\frac{3}{5}} y^{\frac{3}{2}}

2 x^{\frac{1}{5}} y \cdot 10 x^{\frac{1}{3}} = 20 x^{\frac{8}{15}} y

= 8 x^{\frac{3}{5}} y^{\frac{3}{2}} - 20 x^{\frac{8}{15}} y

c a r t ec iana s (1, - 2) p e n d i e n t e - 3

F (0, - 4)

\frac{6 x ^{4} ( - 24 x ^{6} + 25 y ^{5} )}{25 y ^{9}}

(x - 2) (x - 3) (x + 3)

\frac{2 x ^{3} - 6 x}{( x ^{2} + 1 ) ^{3}}

What is expand 2x^{1/5}y(4x^{2/5}y^{1/2}-10x^{1/3}) ?
The solution to expand 2x^{1/5}y(4x^{2/5}y^{1/2}-10x^{1/3}) is 8x^{3/5}y^{3/2}-20x^{8/15}y