What is expand (2+x)e^{1/x} ?

The solution to expand (2+x)e^{1/x} is 2e^{1/x}+e^{1/x}x

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expand (2+x)e^{1/x}

expand

(2 + x) e^{\frac{1}{x}}

2 e^{\frac{1}{x}} + e^{\frac{1}{x}} x

Solution steps

(2 + x) e^{\frac{1}{x}}

= e^{\frac{1}{x}} (2 + x)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{\frac{1}{x}}, b = 2, c = x

= e^{\frac{1}{x}} \cdot 2 + e^{\frac{1}{x}} x

= 2 e^{\frac{1}{x}} + e^{\frac{1}{x}} x

36 \cdot 35 \cdot 34 \cdot 33 \cdot 32 \cdot 31 \cdot 30

(1 - x 2)^{2}

(x + i y) cos (x + i y)

7 (3 x + 2 y = - 7)

3 (sin (2 x) cos (x) - sin^{3} (x))

What is expand (2+x)e^{1/x} ?
The solution to expand (2+x)e^{1/x} is 2e^{1/x}+e^{1/x}x