What is expand (9(2-3s)(s+1))/4 ?

The solution to expand (9(2-3s)(s+1))/4 is -(27s^2)/4-(9s)/4+9/2

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expand (9(2-3s)(s+1))/4

expand

\frac{9 ( 2 - 3 s ) ( s + 1 )}{4}

- \frac{27 s ^{2}}{4} - \frac{9 s}{4} + \frac{9}{2}

Solution steps

\frac{9 ( 2 - 3 s ) ( s + 1 )}{4}

Expand

9 (2 - 3 s) (s + 1) : - 27 s^{2} - 9 s + 18

= \frac{- 27 s ^{2} - 9 s + 18}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 27 s ^{2} - 9 s + 18}{4} = - \frac{27 s ^{2}}{4} - \frac{9 s}{4} + \frac{18}{4}

= - \frac{27 s ^{2}}{4} - \frac{9 s}{4} + \frac{18}{4}

Cancel

\frac{18}{4} : \frac{9}{2}

= - \frac{27 s ^{2}}{4} - \frac{9 s}{4} + \frac{9}{2}

5 H (t - 6) e^{\frac{1}{2} (6 - t)}

- 2 (2 + 1)

(d - e)^{2}

\frac{768}{( s ^{2} + 6 s + 25 ) ^{2}}

\frac{2 s - 7}{( s - 4 ) ( s + 6 )}

What is expand (9(2-3s)(s+1))/4 ?
The solution to expand (9(2-3s)(s+1))/4 is -(27s^2)/4-(9s)/4+9/2