What is expand ((x-1)(x+3))/(x+2) ?

The solution to expand ((x-1)(x+3))/(x+2) is (x^2+2x-3)/(x+2)

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expand ((x-1)(x+3))/(x+2)

expand

\frac{( x - 1 ) ( x + 3 )}{x + 2}

\frac{x ^{2} + 2 x - 3}{x + 2}

Solution steps

\frac{( x - 1 ) ( x + 3 )}{x + 2}

Expand

(x - 1) (x + 3) : x^{2} + 2 x - 3

= \frac{x ^{2} + 2 x - 3}{x + 2}

\frac{2 x + 3}{( x + 2 ) ^{3}}

(1, 9) y (- 6, - 1)

\frac{d}{d x} ((3 x + 2) (8)) + (4 x^{2} + 1) (3)

\frac{1}{2} (3 + 4 t - 10)

e^{t - 6} u (t - 6)

What is expand ((x-1)(x+3))/(x+2) ?
The solution to expand ((x-1)(x+3))/(x+2) is (x^2+2x-3)/(x+2)