What is expand (7x(x+1))/((x+3)(x-3)) ?

The solution to expand (7x(x+1))/((x+3)(x-3)) is (7x^2+7x)/(x^2-9)

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expand (7x(x+1))/((x+3)(x-3))

expand

\frac{7 x ( x + 1 )}{( x + 3 ) ( x - 3 )}

\frac{7 x ^{2} + 7 x}{x ^{2} - 9}

Solution steps

\frac{7 x ( x + 1 )}{( x + 3 ) ( x - 3 )}

Expand

(x + 3) (x - 3) : x^{2} - 9

= \frac{7 x ( x + 1 )}{x ^{2} - 9}

Expand

7 x (x + 1) : 7 x^{2} + 7 x

= \frac{7 x ^{2} + 7 x}{x ^{2} - 9}

8 (2 x ln (x) + x)

x (\frac{100}{x - 8} + 5)

\frac{( x ^{6} + 4 ) ^{2}}{16 x ^{6}}

(sec^{3} (y)) (2 x sin (y) - cos^{3} (y))

\frac{- 2 x ( x + 1 ) e ^{2} + 3 e ^{2 x} - 3}{2 e ^{2}}

What is expand (7x(x+1))/((x+3)(x-3)) ?
The solution to expand (7x(x+1))/((x+3)(x-3)) is (7x^2+7x)/(x^2-9)