What is expand (e^{3x}-e^{-3x})(e^{3x}+e^{-3x}) ?

The solution to expand (e^{3x}-e^{-3x})(e^{3x}+e^{-3x}) is e^{6x}-e^{-6x}

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expand (e^{3x}-e^{-3x})(e^{3x}+e^{-3x})

expand

(e^{3 x} - e^{- 3 x}) (e^{3 x} + e^{- 3 x})

e^{6 x} - e^{- 6 x}

Solution steps

(e^{3 x} - e^{- 3 x}) (e^{3 x} + e^{- 3 x})

Apply Difference of Two Squares Formula:

(a - b) (a + b) = a^{2} - b^{2}

a = e^{3 x}, b = e^{- 3 x}

= (e^{3 x})^{2} - (e^{- 3 x})^{2}

Simplify

(e^{3 x})^{2} - (e^{- 3 x})^{2} : e^{6 x} - e^{- 6 x}

= e^{6 x} - e^{- 6 x}

- 3 (5 + 7)

a (1, - 3) b (5, 6)

5 (sin (x) + x cos (x))

\frac{( n + 1 ) ^{4} + 2 ( n + 1 ) ^{3} + ( n + 1 ) ^{2}}{4}

\frac{\partial}{\partial x} ((z) (e^{x yz} - x - y))

What is expand (e^{3x}-e^{-3x})(e^{3x}+e^{-3x}) ?
The solution to expand (e^{3x}-e^{-3x})(e^{3x}+e^{-3x}) is e^{6x}-e^{-6x}