What is expand (p+2)/((p+1)(p-2)(p^2+4)) ?

The solution to expand (p+2)/((p+1)(p-2)(p^2+4)) is (p+2)/(p^4+2p^2-p^3-4p-8)

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expand (p+2)/((p+1)(p-2)(p^2+4))

expand

\frac{p + 2}{( p + 1 ) ( p - 2 ) ( p ^{2} + 4 )}

\frac{p + 2}{p ^{4} + 2 p ^{2} - p ^{3} - 4 p - 8}

Solution steps

\frac{p + 2}{( p + 1 ) ( p - 2 ) ( p ^{2} + 4 )}

Expand

(p + 1) (p - 2) (p^{2} + 4) : p^{4} + 2 p^{2} - p^{3} - 4 p - 8

= \frac{p + 2}{p ^{4} + 2 p ^{2} - p ^{3} - 4 p - 8}

(- 2 x^{2} + 9 x)^{2}

\frac{( k + 1 ) ^{2} ( k + 2 ) ^{2}}{4} + (k + 1)

- \frac{4}{s ^{2} ( s - 6 )}

\frac{5 x + 3}{( 2 x + 1 ) ( x + 1 ) ^{2}}

(5 x - \frac{1}{2 x ^{3}})^{8}

What is expand (p+2)/((p+1)(p-2)(p^2+4)) ?
The solution to expand (p+2)/((p+1)(p-2)(p^2+4)) is (p+2)/(p^4+2p^2-p^3-4p-8)