What is the d/(dy)((x)(x^y+1/(x^2))) ?

The d/(dy)((x)(x^y+1/(x^2))) is x^{1+y}ln(x)

What is the first d/(dy)((x)(x^y+1/(x^2))) ?

The first d/(dy)((x)(x^y+1/(x^2))) is x^{1+y}ln(x)

Popular >

\frac{d}{d y} ((x) (x^{y} + \frac{1}{x ^{2}}))

x^{1 + y} ln (x)

Solution steps

\frac{d}{d y} ((x) (x^{y} + \frac{1}{x ^{2}}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (x^{y} + \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d y} (x^{y}) + \frac{d}{d y} (\frac{1}{x ^{2}}))

\frac{d}{d y} (x^{y}) = x^{y} ln (x)

\frac{d}{d y} (\frac{1}{x ^{2}}) = 0

= x (x^{y} ln (x) + 0)

Simplify

x (x^{y} ln (x) + 0) : x^{1 + y} ln (x)

= x^{1 + y} ln (x)

(4 e - 2 x)^{3}

(2 x - 5) (3 x^{2} + 4 x) d x

\frac{x ^{2} + 2 x - 1}{( x ^{2} - x - 2 ) ^{2}}

5 (2 + 3)

(e^{i t} - e^{- i t})^{5}

What is the d/(dy)((x)(x^y+1/(x^2))) ?
The d/(dy)((x)(x^y+1/(x^2))) is x^{1+y}ln(x)
What is the first d/(dy)((x)(x^y+1/(x^2))) ?
The first d/(dy)((x)(x^y+1/(x^2))) is x^{1+y}ln(x)