What is expand (d^2y)/((dx)^2)(x^2+y^2=1) ?

The solution to expand (d^2y)/((dx)^2)(x^2+y^2=1) is y+(y^3)/(x^2)=1

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expand (d^2y)/((dx)^2)(x^2+y^2=1)

expand

\frac{d ^{2} y}{( d x ) ^{2}} (x^{2} + y^{2} = 1)

y + \frac{y ^{3}}{x ^{2}} = 1

Solution steps

\frac{d ^{2} y}{( d x ) ^{2}} (x^{2} + y^{2} = 1)

= \frac{d ^{2} y}{( d x ) ^{2}} (x^{2} + 1 = y^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{d ^{2} y}{( d x ) ^{2}}, b = x^{2}, c = y^{2} = 1

\frac{d ^{2} y}{( d x ) ^{2}} x^{2} + \frac{d ^{2} y}{( d x ) ^{2}} y^{2} = 1

Expand

\frac{d ^{2} y}{( d x ) ^{2}} x^{2} + \frac{d ^{2} y}{( d x ) ^{2}} y^{2} : y + \frac{y ^{3}}{x ^{2}}

y + \frac{y ^{3}}{x ^{2}} = 1

d C a (1 - x)

\frac{2}{5} - \frac{2}{7} 0.76 + \frac{1}{2} (0.76 + \frac{1}{3})

\frac{( 2 m + 1 ) ( 2 m + 5 )}{2 ( 2 m + 3 ) ( m + 1 )}

(x + 2) \cdot (x - 2)

(x + i y)^{3} + (x + i y)^{2}

What is expand (d^2y)/((dx)^2)(x^2+y^2=1) ?
The solution to expand (d^2y)/((dx)^2)(x^2+y^2=1) is y+(y^3)/(x^2)=1