What is (x/4-1/3)(x/4+1/3) ?

The solution to (x/4-1/3)(x/4+1/3) is ((3x-4)(3x+4))/(144)

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simplify (x/4-1/3)(x/4+1/3)

simplify

(\frac{x}{4} - \frac{1}{3}) (\frac{x}{4} + \frac{1}{3})

\frac{( 3 x - 4 ) ( 3 x + 4 )}{144}

Solution steps

(\frac{x}{4} - \frac{1}{3}) (\frac{x}{4} + \frac{1}{3})

Simplify

\frac{x}{4} - \frac{1}{3} : \frac{3 x - 4}{12}

= \frac{3 x - 4}{12} (\frac{x}{4} + \frac{1}{3})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 x - 4 ) ( \frac{x}{4} + \frac{1}{3} )}{12}

Simplify

(3 x - 4) (\frac{x}{4} + \frac{1}{3}) : \frac{( 3 x - 4 ) ( x \cdot 3 + 4 )}{12}

= \frac{\frac{( 3 x - 4 ) ( x \cdot 3 + 4 )}{12}}{12}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 x - 4 ) ( x \cdot 3 + 4 )}{12 \cdot 12}

Multiply the numbers:

12 \cdot 12 = 144

= \frac{( 3 x - 4 ) ( x \cdot 3 + 4 )}{144}

= \frac{( 3 x - 4 ) ( 3 x + 4 )}{144}

cos^{3} (y) (2 x sin (y) - cos^{3} (y))

(- 2 5 h + 9 + 6) 5 h + 9

(25 - 3)^{2}

A (- 1, 3) B (2, 0) C (1, - 1)

(x + x y^{2}) d x + x^{2} y d y

What is (x/4-1/3)(x/4+1/3) ?
The solution to (x/4-1/3)(x/4+1/3) is ((3x-4)(3x+4))/(144)