What is expand+P(-1,8)yQ(5,-6) ?

The solution to expand+P(-1,8)yQ(5,-6) is 5(-1*8,)PyQ,-6(-1*8,)PyQ

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expand+P(-1,8)yQ(5,-6)

expand

+ P (- 1, 8) y Q (5, - 6)

5 (- 1 \cdot 8,) P y Q, - 6 (- 1 \cdot 8,) P y Q

Solution steps

P (- 1, 8) y Q (5, - 6)

= (- 1 \cdot 8,) (5, - 6) P y Q

Apply the distributive law:

a (b - c) = ab - a c

a = P (- 1, 8) y Q, b = 5,, c = 6

= P (- 1, 8) y Q \cdot 5, - P (- 1, 8) y Q \cdot 6

= 5 (- 1 \cdot 8,) P y Q, - 6 (- 1 \cdot 8,) P y Q

2 y (1 - 2 x^{2}) e^{- x^{2} - y^{2}}

(8) (4) (- 4) (- 8) (- 12) (- 16)

(2 sec (x) - 1)^{2}

\frac{2}{( 4 n - 3 ) ( 4 n + 1 )}

e^{x} (x^{2} + 5 x + 6)

What is expand+P(-1,8)yQ(5,-6) ?
The solution to expand+P(-1,8)yQ(5,-6) is 5(-1*8,)PyQ,-6(-1*8,)PyQ