What is factor 25u^2-40u+16 ?

The solution to factor 25u^2-40u+16 is (5u-4)^2

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factor 25u^2-40u+16

factor

25 u^{2} - 40 u + 16

(5 u - 4)^{2}

Solution steps

25 u^{2} - 40 u + 16

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 u^{2} = (5 u)^{2}

16 = 4^{2}

- 40 u = - 2 \cdot 5 u \cdot 4

= (5 u)^{2} - 2 \cdot 5 u \cdot 4 + 4^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(5 u)^{2} - 2 \cdot 5 u \cdot 4 + 4^{2} = (5 u - 4)^{2}

= (5 u - 4)^{2}

- 3 x^{2} + 224 = - 6 x + 2

\frac{5 x}{9} - \frac{x}{9} = 3

\frac{5}{2} \cdot \frac{7}{10}

\frac{1}{2 + 5}

\frac{1}{4 ^{- 1}}