What is expand ((7-3x)/4)^2 ?

The solution to expand ((7-3x)/4)^2 is (9x^2}{16}-\frac{21x)/8+49/16

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expand ((7-3x)/4)^2

expand

(\frac{7 - 3 x}{4})^{2}

\frac{9 x ^{2}}{16} - \frac{21 x}{8} + \frac{49}{16}

Solution steps

(\frac{7 - 3 x}{4})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 7 - 3 x ) ^{2}}{4 ^{2}}

(7 - 3 x)^{2} = 49 - 42 x + 9 x^{2}

= \frac{49 - 42 x + 9 x ^{2}}{4 ^{2}}

4^{2} = 16

= \frac{49 - 42 x + 9 x ^{2}}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{49 - 42 x + 9 x ^{2}}{16} = \frac{49}{16} - \frac{42 x}{16} + \frac{9 x ^{2}}{16}

= \frac{49}{16} - \frac{42 x}{16} + \frac{9 x ^{2}}{16}

Cancel

\frac{42 x}{16} : \frac{21 x}{8}

= \frac{49}{16} - \frac{21 x}{8} + \frac{9 x ^{2}}{16}

Rewrite in standard form

= \frac{9 x ^{2}}{16} - \frac{21 x}{8} + \frac{49}{16}

x 3 (2 x + 45)

\frac{S + 3}{S ^{2} ( S - 2 ) ^{2}}

\frac{( 2 y - 3 ) ^{2}}{4}

(4 x + 7)^{4} d x

\frac{1}{( s + 2 ) ^{3}}

What is expand ((7-3x)/4)^2 ?
The solution to expand ((7-3x)/4)^2 is (9x^2}{16}-\frac{21x)/8+49/16