What is expand (k^7+3)/(2k^4) ?

The solution to expand (k^7+3)/(2k^4) is (k^3)/2+3/(2k^4)

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expand (k^7+3)/(2k^4)

expand

\frac{k ^{7} + 3}{2 k ^{4}}

\frac{k ^{3}}{2} + \frac{3}{2 k ^{4}}

Solution steps

\frac{k ^{7} + 3}{2 k ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{k ^{7} + 3}{2 k ^{4}} = \frac{k ^{7}}{2 k ^{4}} + \frac{3}{2 k ^{4}}

= \frac{k ^{7}}{2 k ^{4}} + \frac{3}{2 k ^{4}}

Cancel

\frac{k ^{7}}{2 k ^{4}} : \frac{k ^{3}}{2}

= \frac{k ^{3}}{2} + \frac{3}{2 k ^{4}}

(1 + 21 t)^{2} + (1 + 21 t)^{2}

A (5, - 6) B (- 7, 2)

\frac{d}{d t} ((x) (t^{3} - t^{2}))

- 36 (x - \frac{1}{4}) (x - 1)

\frac{2 y ^{2} ( 3 y ^{3} + 1 )}{19}

What is expand (k^7+3)/(2k^4) ?
The solution to expand (k^7+3)/(2k^4) is (k^3)/2+3/(2k^4)