What is expand ((16-x)^2x)/(32) ?

The solution to expand ((16-x)^2x)/(32) is (x^3)/(32)-x^2+8x

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expand ((16-x)^2x)/(32)

expand

\frac{( 16 - x ) ^{2} x}{32}

\frac{x ^{3}}{32} - x^{2} + 8 x

Solution steps

\frac{( 16 - x ) ^{2} x}{32}

(16 - x)^{2} = 256 - 32 x + x^{2}

= \frac{x ( x ^{2} - 32 x + 256 )}{32}

Expand

(256 - 32 x + x^{2}) x : 256 x - 32 x^{2} + x^{3}

= \frac{256 x - 32 x ^{2} + x ^{3}}{32}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{256 x - 32 x ^{2} + x ^{3}}{32} = \frac{256 x}{32} - \frac{32 x ^{2}}{32} + \frac{x ^{3}}{32}

= \frac{256 x}{32} - \frac{32 x ^{2}}{32} + \frac{x ^{3}}{32}

Divide the numbers:

\frac{256}{32} = 8

= 8 x - \frac{32 x ^{2}}{32} + \frac{x ^{3}}{32}

Divide the numbers:

\frac{32}{32} = 1

= 8 x - x^{2} + \frac{x ^{3}}{32}

Rewrite in standard form

= \frac{x ^{3}}{32} - x^{2} + 8 x

(1 + cos (x))^{4} \cdot sin (x)

\frac{1}{10} (e^{x} - e^{- x})

x^{3} δ (x - 2)

v (- 3, - 2) f (1, - 2)

(A e^{i x} + B e^{- i x})^{2}

What is expand ((16-x)^2x)/(32) ?
The solution to expand ((16-x)^2x)/(32) is (x^3)/(32)-x^2+8x