What is expand-sin(θ)(1-x^2) ?

The solution to expand-sin(θ)(1-x^2) is -sin(θ)+x^2sin(θ)

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expand-sin(θ)(1-x^2)

expand

- sin (θ) (1 - x^{2})

- sin (θ) + x^{2} sin (θ)

Solution steps

- sin (θ) (1 - x^{2})

Apply the distributive law:

a (b - c) = ab - a c

- sin (θ) (1 - x^{2}) = - sin (θ) \cdot 1 - (- sin (θ)) x^{2}

= - sin (θ) \cdot 1 - (- sin (θ)) x^{2}

Simplify

- sin (θ) \cdot 1 - (- sin (θ)) x^{2} : - sin (θ) + x^{2} sin (θ)

= - sin (θ) + x^{2} sin (θ)

x (2 - x^{2})

\frac{d}{d ^{4}} (y = 2 x^{4} - 6 x^{3} + 7 x^{2} + 5 x)

(y - 2) + (x + 7) y^{'} (x)

(1 - t) \cdot (0, 1, 0)

3 x^{2} e^{3 x} (1 + x)

What is expand-sin(θ)(1-x^2) ?
The solution to expand-sin(θ)(1-x^2) is -sin(θ)+x^2sin(θ)