What is expand 1/4 (2x+3y)-(2y-x)/(12)-2/3 (x-y) ?

The solution to expand 1/4 (2x+3y)-(2y-x)/(12)-2/3 (x-y) is (2x+3y)/4-(2y-x}{12}+\frac{-2x+2y)/3

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expand 1/4 (2x+3y)-(2y-x)/(12)-2/3 (x-y)

expand

\frac{1}{4} (2 x + 3 y) - \frac{2 y - x}{12} - \frac{2}{3} (x - y)

\frac{2 x + 3 y}{4} - \frac{2 y - x}{12} + \frac{- 2 x + 2 y}{3}

Solution steps

\frac{1}{4} (2 x + 3 y) - \frac{2 y - x}{12} - \frac{2}{3} (x - y)

Expand

\frac{1}{4} (2 x + 3 y) : \frac{2 x + 3 y}{4}

= \frac{2 x + 3 y}{4} - \frac{2 y - x}{12} - \frac{2}{3} (x - y)

Expand

- \frac{2}{3} (x - y) : - \frac{2}{3} x + \frac{2}{3} y

= \frac{2 x + 3 y}{4} - \frac{2 y - x}{12} - \frac{2}{3} x + \frac{2}{3} y

Simplify

\frac{2 x + 3 y}{4} - \frac{2 y - x}{12} - \frac{2}{3} x + \frac{2}{3} y : \frac{2 x + 3 y}{4} - \frac{2 y - x}{12} + \frac{- 2 x + 2 y}{3}

= \frac{2 x + 3 y}{4} - \frac{2 y - x}{12} + \frac{- 2 x + 2 y}{3}

(3 y + 2) (3 x^{\frac{3}{2}} + 2 x^{\frac{1}{2}})

sin ((π - 1) n)

(4 x y^{2} + 3 y) d x

\frac{( x - 8 ) ^{2}}{x ^{2} - 16}

\frac{( 2 t - 3 ) ^{2}}{t}

What is expand 1/4 (2x+3y)-(2y-x)/(12)-2/3 (x-y) ?
The solution to expand 1/4 (2x+3y)-(2y-x)/(12)-2/3 (x-y) is (2x+3y)/4-(2y-x}{12}+\frac{-2x+2y)/3