What is expand (2x^2-7x+3)/((x+1)(x-1)) ?

The solution to expand (2x^2-7x+3)/((x+1)(x-1)) is (2x^2-7x+3)/(x^2-1)

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expand (2x^2-7x+3)/((x+1)(x-1))

expand

\frac{2 x ^{2} - 7 x + 3}{( x + 1 ) ( x - 1 )}

\frac{2 x ^{2} - 7 x + 3}{x ^{2} - 1}

Solution steps

\frac{2 x ^{2} - 7 x + 3}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{2 x ^{2} - 7 x + 3}{x ^{2} - 1}

(x - 3)^{2} + (y - 2)^{2}

(3 e^{3 t} - e^{- t}) \times (9 e^{6 t} + e^{- 2 t})

\frac{s ^{2} + 2 s + 3}{( s ^{2} + 2 s + 2 ) ( s ^{2} + 2 s + 5 )}

A (31, 6) B (- 31, - 2)

2 + 3 - (1 + 2) in

What is expand (2x^2-7x+3)/((x+1)(x-1)) ?
The solution to expand (2x^2-7x+3)/((x+1)(x-1)) is (2x^2-7x+3)/(x^2-1)