What is expand (-2a-1/3)^3 ?

The solution to expand (-2a-1/3)^3 is (-216a^3-108a^2-18a-1)/(27)

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expand (-2a-1/3)^3

expand

(- 2 a - \frac{1}{3})^{3}

\frac{- 216 a ^{3} - 108 a ^{2} - 18 a - 1}{27}

Solution steps

(- 2 a - \frac{1}{3})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(- 2 a - \frac{1}{3})^{3} = (- 2 a)^{3} - 3 (- 2 a)^{2} \frac{1}{3} + 3 (- 2 a) (\frac{1}{3})^{2} - (\frac{1}{3})^{3}

= (- 2 a)^{3} - 3 (- 2 a)^{2} \frac{1}{3} + 3 (- 2 a) (\frac{1}{3})^{2} - (\frac{1}{3})^{3}

Simplify

(- 2 a)^{3} - 3 (- 2 a)^{2} \frac{1}{3} + 3 (- 2 a) (\frac{1}{3})^{2} - (\frac{1}{3})^{3} : \frac{- 216 a ^{3} - 108 a ^{2} - 18 a - 1}{27}

= \frac{- 216 a ^{3} - 108 a ^{2} - 18 a - 1}{27}

\frac{5 x - 2}{( - 2 x - 9 ) ( 2 x - 2 )}

x - 9 (x + 3)

\frac{45.78}{s ^{2} ( s ^{2} + 8 s + 45.78 )}

x^{\frac{3}{2}} (1 - x)^{2}

- 16 (3 x^{2} sin (x^{4}) + 4 x^{6} cos (x^{4}))

What is expand (-2a-1/3)^3 ?
The solution to expand (-2a-1/3)^3 is (-216a^3-108a^2-18a-1)/(27)