What is expand 1/((x^2+1)(x+1)) ?

The solution to expand 1/((x^2+1)(x+1)) is 1/(x^3+x^2+x+1)

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expand 1/((x^2+1)(x+1))

expand

\frac{1}{( x ^{2} + 1 ) ( x + 1 )}

\frac{1}{x ^{3} + x ^{2} + x + 1}

Solution steps

\frac{1}{( x ^{2} + 1 ) ( x + 1 )}

Expand

(x^{2} + 1) (x + 1) : x^{3} + x^{2} + x + 1

= \frac{1}{x ^{3} + x ^{2} + x + 1}

(2 u, 2 v, 1) \cdot (9 - u^{2} - v^{2}, 9 - u^{2} - v^{2}, u)

\frac{n ^{2}}{( - 2 i d x + 2 i ^{2} d ^{2} ) ( s + x - i d )}

(- 4 x^{2} + 6 y^{2} + 2 x + 1 = 0) \frac{- 1}{4}

(x) \cdot (1 + x + 1 - x)

x (ln (x) - 1)^{2}

What is expand 1/((x^2+1)(x+1)) ?
The solution to expand 1/((x^2+1)(x+1)) is 1/(x^3+x^2+x+1)