What is expand ((x+7)(x-2))/(2(x^2-3)) ?

The solution to expand ((x+7)(x-2))/(2(x^2-3)) is (x^2+5x-14)/(2x^2-6)

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expand ((x+7)(x-2))/(2(x^2-3))

expand

\frac{( x + 7 ) ( x - 2 )}{2 ( x ^{2} - 3 )}

\frac{x ^{2} + 5 x - 14}{2 x ^{2} - 6}

Solution steps

\frac{( x + 7 ) ( x - 2 )}{2 ( x ^{2} - 3 )}

Expand

2 (x^{2} - 3) : 2 x^{2} - 6

= \frac{( x + 7 ) ( x - 2 )}{2 x ^{2} - 6}

Expand

(x + 7) (x - 2) : x^{2} + 5 x - 14

= \frac{x ^{2} + 5 x - 14}{2 x ^{2} - 6}

\frac{1}{( x + 2 ) ( x - 2 )}

(1 + 10 - x)^{2}

\frac{2 x y}{( x ^{2} + y ^{2} ) ^{2}}

(y + \frac{x + y}{x}) ln (x y)

\frac{7 u ( 4 u - 1 ) ( 3 u - 1 )}{4 u + 5}

What is expand ((x+7)(x-2))/(2(x^2-3)) ?
The solution to expand ((x+7)(x-2))/(2(x^2-3)) is (x^2+5x-14)/(2x^2-6)