What is expand ((x^2+6x+9))/((x^2-9)) ?

The solution to expand ((x^2+6x+9))/((x^2-9)) is (x+3)/(x-3)

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expand ((x^2+6x+9))/((x^2-9))

expand

\frac{( x ^{2} + 6 x + 9 )}{( x ^{2} - 9 )}

\frac{x + 3}{x - 3}

Solution steps

\frac{x ^{2} + 6 x + 9}{x ^{2} - 9}

Factor

x^{2} + 6 x + 9 : (x + 3)^{2}

= \frac{( x + 3 ) ^{2}}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ^{2}}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x + 3

= \frac{x + 3}{x - 3}

x (ln (u) - 2) u z

2 (j ln (t) + j - \frac{k}{t})

8 1^{u (7 p + 7 q)}

(1 - tan (x))^{5}

(y sin (x) + x sin (y)) d x + n (x, y) d y

What is expand ((x^2+6x+9))/((x^2-9)) ?
The solution to expand ((x^2+6x+9))/((x^2-9)) is (x+3)/(x-3)