What is the answer to 0y-2=19-4y+1y ?

The answer to 0y-2=19-4y+1y is y=7

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0y-2=19-4y+1y

0 y - 2 = 19 - 4 y + 1 y

y = 7

Solution steps

0 \cdot y - 2 = 19 - 4 y + 1 \cdot y

Apply rule

0 \cdot a = 0

0 - 2 = 19 - 4 y + 1 \cdot y

Subtract the numbers:

0 - 2 = - 2

- 2 = 19 - 4 y + 1 \cdot y

Add similar elements:

- 4 y + 1 \cdot y = - 3 y

- 2 = 19 - 3 y

Move

2

to the right side

0 = - 3 y + 21

Move

0

to the right side

= - 3 y + 21

Move

3 y

to the left side

3 y = 21

Divide both sides by

3

y = 7

16 q^{2} + 56 q + 49

9^{\frac{3}{4}} \cdot 3^{- \frac{1}{2}}

x + \frac{1}{x - 2} + \frac{2}{( x + 6 ) ( x - 2 )} - 2 \geq x - \frac{3}{x + 6} - 2

(x - 3)^{2} (x + 6) > 0

(9^{\frac{5}{3}})^{\frac{3}{10}}