What is expand a(2tu+u+t^2)de(-t^2-4tu) ?

The solution to expand a(2tu+u+t^2)de(-t^2-4tu) is -6deat^3u-deat^2u-deat^4-8deat^2u^2-4deatu^2

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expand a(2tu+u+t^2)de(-t^2-4tu)

expand

a (2 t u + u + t^{2}) d e (- t^{2} - 4 t u)

- 6 d e a t^{3} u - d e a t^{2} u - d e a t^{4} - 8 d e a t^{2} u^{2} - 4 d e a t u^{2}

Solution steps

a (2 t u + u + t^{2}) d e (- t^{2} - 4 t u)

= d e a (2 t u + u + t^{2}) (- t^{2} - 4 t u)

Expand

(2 t u + u + t^{2}) (- t^{2} - 4 t u) : - 6 t^{3} u - t^{2} u - t^{4} - 8 t^{2} u^{2} - 4 t u^{2}

= a d e (- 6 t^{3} u - t^{2} u - t^{4} - 8 t^{2} u^{2} - 4 t u^{2})

Expand

a d e (- 6 t^{3} u - t^{2} u - t^{4} - 8 t^{2} u^{2} - 4 t u^{2}) : - 6 d e a t^{3} u - d e a t^{2} u - d e a t^{4} - 8 d e a t^{2} u^{2} - 4 d e a t u^{2}

= - 6 d e a t^{3} u - d e a t^{2} u - d e a t^{4} - 8 d e a t^{2} u^{2} - 4 d e a t u^{2}

a^{(x - 2) \cdot 2}

- \frac{2 ( 2 x + 3 ) ( - x ^{2} - 3 x - 39 )}{( x ^{2} + 3 x - 10 ) ^{3}}

\frac{1}{s ( s + 1 ) ( s + 2 )}

(x cos (a) - y sin (a))^{2}

\frac{3}{2} \cdot (1 - \frac{3}{4})

What is expand a(2tu+u+t^2)de(-t^2-4tu) ?
The solution to expand a(2tu+u+t^2)de(-t^2-4tu) is -6deat^3u-deat^2u-deat^4-8deat^2u^2-4deatu^2