What is expand (x^3-4x^2+x-4)(x^2=18x+82) ?

The solution to expand (x^3-4x^2+x-4)(x^2=18x+82) is x^5=18x-328

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expand (x^3-4x^2+x-4)(x^2=18x+82)

expand

(x^{3} - 4 x^{2} + x - 4) (x^{2} = 18 x + 82)

x^{5} = 18 x - 328

Solution steps

(x^{3} - 4 x^{2} + x - 4) (x^{2} = 18 x + 82)

= (x^{3} - 4 x^{2} + x - 4) (18 = x^{2} x + 82)

Distribute parentheses

x^{3} x^{2} = 18 x + x^{3} \cdot 82 + (- 4 x^{2}) x^{2} = 18 x + (- 4 x^{2}) \cdot 82 + x x^{2} = 18 x + x \cdot 82 + (- 4) x^{2} = 18 x + (- 4) \cdot 82

Apply minus-plus rules

+ (- a) = - a

x^{3} x^{2} = 18 x + 82 x^{3} - 4 x^{2} x^{2} = 18 x - 4 \cdot 82 x^{2} + x^{2} x = 18 x + 82 x - 4 x^{2} = 18 x - 4 \cdot 82

Simplify

x^{3} x^{2} = 18 x + 82 x^{3} - 4 x^{2} x^{2} = 18 x - 4 \cdot 82 x^{2} + x^{2} x = 18 x + 82 x - 4 x^{2} = 18 x - 4 \cdot 82 : x^{5} = 18 x - 328

x^{5} = 18 x - 328

\frac{( x ) ( 2 x + 1 )}{2}

x^{3} + 10 x^{2} + 23 x^{1} + 14

\frac{1}{x ( a - b x ^{2} )}

(2 x^{2} - 5 x - 8)^{2}

\frac{7 x ^{2} - 9 x + 4}{( x - 1 ) ( x ^{2} + 2 )}

What is expand (x^3-4x^2+x-4)(x^2=18x+82) ?
The solution to expand (x^3-4x^2+x-4)(x^2=18x+82) is x^5=18x-328