What are the solutions to the equation x^2-10x+25=3 ?

The solutions to the equation x^2-10x+25=3 are x=5+sqrt(3),x=5-sqrt(3)

Find the zeros of x^2-10x+25=3

The zeros of x^2-10x+25=3 are x=5+sqrt(3),x=5-sqrt(3)

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x^{2} - 10 x + 25 = 3

x = 5 + 3, x = 5 - 3

Solution steps

x^{2} - 10 x + 25 = 3

Move

3

to the left side

x^{2} - 10 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 22 = 23

x_{1, 2} = \frac{- ( - 10 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 3}{2 \cdot 1} : 5 + 3

x = \frac{- ( - 10 ) - 2 3}{2 \cdot 1} : 5 - 3

The solutions to the quadratic equation are:

x = 5 + 3, x = 5 - 3

\frac{3 x}{2} + \frac{1}{6} = \frac{2 x}{3} - \frac{2}{3}

\frac{5}{10}

6 - 1

x^{2} + x + 2 \geq 0

∣ x + 6 ∣ = 2 x - 3

What are the solutions to the equation x^2-10x+25=3 ?
The solutions to the equation x^2-10x+25=3 are x=5+sqrt(3),x=5-sqrt(3)
Find the zeros of x^2-10x+25=3
The zeros of x^2-10x+25=3 are x=5+sqrt(3),x=5-sqrt(3)