What is expand ((-1)^nn!)/(2^n(n+1)) ?

The solution to expand ((-1)^nn!)/(2^n(n+1)) is ((-1)^nn!)/(2^nn+2^n)

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expand ((-1)^nn!)/(2^n(n+1))

expand

\frac{( - 1 ) ^{n} n !}{2 ^{n} ( n + 1 )}

\frac{( - 1 ) ^{n} n !}{2 ^{n} n + 2 ^{n}}

Solution steps

\frac{( - 1 ) ^{n} n !}{2 ^{n} ( n + 1 )}

Expand

2^{n} (n + 1) : 2^{n} n + 2^{n}

= \frac{( - 1 ) ^{n} n !}{2 ^{n} n + 2 ^{n}}

\frac{- 2 x - 10}{( x + 3 ) ( x + 1 )}

(1 + x^{2}) 1 - x^{2}

(x + \frac{3}{2}) (x + \frac{1}{2})

(e^{x} + 2) (e^{x} + \frac{1}{3})

\frac{( x + 5 ) ( x + 2 )}{x ^{2} - 7}

What is expand ((-1)^nn!)/(2^n(n+1)) ?
The solution to expand ((-1)^nn!)/(2^n(n+1)) is ((-1)^nn!)/(2^nn+2^n)