What is expand (x-2)(x-1/2)(x+4) ?

The solution to expand (x-2)(x-1/2)(x+4) is x^3+(3x^2)/2-9x+4

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expand (x-2)(x-1/2)(x+4)

expand

(x - 2) (x - \frac{1}{2}) (x + 4)

x^{3} + \frac{3 x ^{2}}{2} - 9 x + 4

Solution steps

(x - 2) (x - \frac{1}{2}) (x + 4)

Expand

(x - 2) (x - \frac{1}{2}) (x + 4) : (x^{2} - \frac{5}{2} x + 1) (x + 4)

= (x^{2} - \frac{5}{2} x + 1) (x + 4)

Distribute parentheses

= x^{2} x + x^{2} \cdot 4 - \frac{5}{2} xx - \frac{5}{2} x \cdot 4 + 1 \cdot x + 1 \cdot 4

Simplify

x^{2} x + x^{2} \cdot 4 - \frac{5}{2} xx - \frac{5}{2} x \cdot 4 + 1 \cdot x + 1 \cdot 4 : x^{3} + \frac{3 x ^{2}}{2} - 9 x + 4

= x^{3} + \frac{3 x ^{2}}{2} - 9 x + 4

(csc (x) + 2) (- 2 csc (x) cot (x))

\frac{x}{5 ( x - 1 ) ^{3}}

\frac{4 x - 1}{s ^{2} ( s + 1 ) ^{3}}

y (x + y) d x + \frac{x y + 1}{d y = 0}

(x + 9) (x - \frac{4}{3})

What is expand (x-2)(x-1/2)(x+4) ?
The solution to expand (x-2)(x-1/2)(x+4) is x^3+(3x^2)/2-9x+4