What is 3t(x)x^{''}+2(t(x)-3)x^'-2x ?

The solution to 3t(x)x^{''}+2(t(x)-3)x^'-2x is 3tx^{1+'^2}+2x^'(tx-3)-2x

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simplify 3t(x)x^{''}+2(t(x)-3)x^'-2x

simplify

3 t (x) x^{^{''}} + 2 (t (x) - 3) x^{^{'}} - 2 x

3 t x^{1 +'^{2}} + 2 x^{'} (t x - 3) - 2 x

Solution steps

3 t (x) x^{^{''}} + 2 (t (x) - 3) x^{^{'}} - 2 x

Remove parentheses:

(a) = a

= 3 t x x^{^{^{''}}} + 2 (t x - 3) x^{^{^{'}}} - 2 x

e^{jπ (1 - 2 n)}

- \frac{5 ( x + 16 )}{2}

(x - \frac{b}{3 a})^{3}

(p = 2, r) (q = 2 r + 1)

n e^{x} + m (e^{x} + e^{x} x) - \frac{9}{2} sin (x) + \frac{1}{2} cos (x)

What is 3t(x)x^{''}+2(t(x)-3)x^'-2x ?
The solution to 3t(x)x^{''}+2(t(x)-3)x^'-2x is 3tx^{1+'^2}+2x^'(tx-3)-2x