What is expand (x-9)(x-3)^2ln(x/6) ?

The solution to expand (x-9)(x-3)^2ln(x/6) is x^3ln(x/6)-15x^2ln(x/6)+63xln(x/6)-81ln(x/6)

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expand (x-9)(x-3)^2ln(x/6)

expand

(x - 9) (x - 3)^{2} ln (\frac{x}{6})

x^{3} ln (\frac{x}{6}) - 15 x^{2} ln (\frac{x}{6}) + 63 x ln (\frac{x}{6}) - 81 ln (\frac{x}{6})

Solution steps

(x - 9) (x - 3)^{2} ln (\frac{x}{6})

= ln (\frac{x}{6}) (x - 9) (x - 3)^{2}

Apply the distributive law:

a (b - c) = ab - a c

a = (x - 3)^{2} ln (\frac{x}{6}), b = x, c = 9

= (x - 3)^{2} ln (\frac{x}{6}) x - (x - 3)^{2} ln (\frac{x}{6}) \cdot 9

= x ln (\frac{x}{6}) (x - 3)^{2} - 9 ln (\frac{x}{6}) (x - 3)^{2}

Simplify

x ln (\frac{x}{6}) (x - 3)^{2} - 9 ln (\frac{x}{6}) (x - 3)^{2} : x^{3} ln (\frac{x}{6}) - 15 x^{2} ln (\frac{x}{6}) + 63 x ln (\frac{x}{6}) - 81 ln (\frac{x}{6})

= x^{3} ln (\frac{x}{6}) - 15 x^{2} ln (\frac{x}{6}) + 63 x ln (\frac{x}{6}) - 81 ln (\frac{x}{6})

ln (x) (4 x^{3} + 6 x + 1)

2 j w (2 j w + 1)

(- A k (e^{- k H} + e^{k H}) sin (k x) + 2 B H)^{2}

\frac{p}{3} - (\frac{q}{2})^{2}

(0, - 1) y (1, 0)

What is expand (x-9)(x-3)^2ln(x/6) ?
The solution to expand (x-9)(x-3)^2ln(x/6) is x^3ln(x/6)-15x^2ln(x/6)+63xln(x/6)-81ln(x/6)