What is expand ((6x-1)^2)/4 ?

The solution to expand ((6x-1)^2)/4 is 9x^2-3x+1/4

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expand ((6x-1)^2)/4

expand

\frac{( 6 x - 1 ) ^{2}}{4}

9 x^{2} - 3 x + \frac{1}{4}

Solution steps

\frac{( 6 x - 1 ) ^{2}}{4}

(6 x - 1)^{2} = 36 x^{2} - 12 x + 1

= \frac{36 x ^{2} - 12 x + 1}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{36 x ^{2} - 12 x + 1}{4} = \frac{36 x ^{2}}{4} - \frac{12 x}{4} + \frac{1}{4}

= \frac{36 x ^{2}}{4} - \frac{12 x}{4} + \frac{1}{4}

Divide the numbers:

\frac{36}{4} = 9

= 9 x^{2} - \frac{12 x}{4} + \frac{1}{4}

Divide the numbers:

\frac{12}{4} = 3

= 9 x^{2} - 3 x + \frac{1}{4}

(- 9 + 3) (4 - 7)

- 2 x^{\frac{7}{2}} (x^{2} + 1)

(e^{x} + 1) (\frac{e ^{2 x}}{4 ( e ^{x} + 1 )} + 1)

\frac{2 ( cos ( θ ) + sin ( θ ) )}{sin ( 2 θ ) + cos ( 2 θ ) + 1}

lo g_{e} (2)

What is expand ((6x-1)^2)/4 ?
The solution to expand ((6x-1)^2)/4 is 9x^2-3x+1/4