What is expand ((7m^4+n)^3)/(343) ?

The solution to expand ((7m^4+n)^3)/(343) is m^{12}+(3m^8n)/7+(3m^4n^2)/(49)+(n^3)/(343)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((7m^4+n)^3)/(343)

expand

\frac{( 7 m ^{4} + n ) ^{3}}{343}

m^{12} + \frac{3 m ^{8} n}{7} + \frac{3 m ^{4} n ^{2}}{49} + \frac{n ^{3}}{343}

Solution steps

\frac{( 7 m ^{4} + n ) ^{3}}{343}

(7 m^{4} + n)^{3} = 343 m^{12} + 147 m^{8} n + 21 m^{4} n^{2} + n^{3}

= \frac{343 m ^{12} + 147 m ^{8} n + 21 m ^{4} n ^{2} + n ^{3}}{343}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{343 m ^{12} + 147 m ^{8} n + 21 m ^{4} n ^{2} + n ^{3}}{343} = \frac{343 m ^{12}}{343} + \frac{147 m ^{8} n}{343} + \frac{21 m ^{4} n ^{2}}{343} + \frac{n ^{3}}{343}

= \frac{343 m ^{12}}{343} + \frac{147 m ^{8} n}{343} + \frac{21 m ^{4} n ^{2}}{343} + \frac{n ^{3}}{343}

Divide the numbers:

\frac{343}{343} = 1

= m^{12} + \frac{147 m ^{8} n}{343} + \frac{21 m ^{4} n ^{2}}{343} + \frac{n ^{3}}{343}

Cancel

\frac{147 m ^{8} n}{343} : \frac{3 m ^{8} n}{7}

= m^{12} + \frac{3 m ^{8} n}{7} + \frac{21 m ^{4} n ^{2}}{343} + \frac{n ^{3}}{343}

Cancel

\frac{21 m ^{4} n ^{2}}{343} : \frac{3 m ^{4} n ^{2}}{49}

= m^{12} + \frac{3 m ^{8} n}{7} + \frac{3 m ^{4} n ^{2}}{49} + \frac{n ^{3}}{343}

(- 8 - 9 i)^{6}

\frac{( 6 x + 7 y ) ^{2}}{36 x ^{2} - 84 x y + 49 y ^{2} + 49}

\frac{x ^{2} + 2 x + 7}{( x + 1 ) ^{2}}

What is expand ((7m^4+n)^3)/(343) ?
The solution to expand ((7m^4+n)^3)/(343) is m^{12}+(3m^8n)/7+(3m^4n^2)/(49)+(n^3)/(343)