What is expand (x^4(15y^5-8))/(2y^4) ?

The solution to expand (x^4(15y^5-8))/(2y^4) is (15x^4y)/2-(4x^4)/(y^4)

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expand (x^4(15y^5-8))/(2y^4)

expand

\frac{x ^{4} ( 15 y ^{5} - 8 )}{2 y ^{4}}

\frac{15 x ^{4} y}{2} - \frac{4 x ^{4}}{y ^{4}}

Solution steps

\frac{x ^{4} ( 15 y ^{5} - 8 )}{2 y ^{4}}

Expand

x^{4} (15 y^{5} - 8) : 15 x^{4} y^{5} - 8 x^{4}

= \frac{15 x ^{4} y ^{5} - 8 x ^{4}}{2 y ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{15 x ^{4} y ^{5} - 8 x ^{4}}{2 y ^{4}} = \frac{15 x ^{4} y ^{5}}{2 y ^{4}} - \frac{8 x ^{4}}{2 y ^{4}}

= \frac{15 x ^{4} y ^{5}}{2 y ^{4}} - \frac{8 x ^{4}}{2 y ^{4}}

Cancel

\frac{15 x ^{4} y ^{5}}{2 y ^{4}} : \frac{15 x ^{4} y}{2}

= \frac{15 x ^{4} y}{2} - \frac{8 x ^{4}}{2 y ^{4}}

Divide the numbers:

\frac{8}{2} = 4

= \frac{15 x ^{4} y}{2} - \frac{4 x ^{4}}{y ^{4}}

\frac{2 x ^{5} - 4 x ^{2} - 6 x}{( x ^{2} + 1 ) ^{4}}

\frac{7 s - 6}{( s + 2 ) ( s - 3 )}

3 (x + Δ x) y^{2}

(x - 5 - 3) (x - 5 + 3)

What is expand (x^4(15y^5-8))/(2y^4) ?
The solution to expand (x^4(15y^5-8))/(2y^4) is (15x^4y)/2-(4x^4)/(y^4)