What is expand (e^t+e^{-t})^2 ?

The solution to expand (e^t+e^{-t})^2 is e^{2t}+2+e^{-2t}

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expand (e^t+e^{-t})^2

expand

(e^{t} + e^{- t})^{2}

e^{2 t} + 2 + e^{- 2 t}

Solution steps

(e^{t} + e^{- t})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = e^{t}, b = e^{- t}

= (e^{t})^{2} + 2 e^{t} e^{- t} + (e^{- t})^{2}

Simplify

(e^{t})^{2} + 2 e^{t} e^{- t} + (e^{- t})^{2} : e^{2 t} + 2 + e^{- 2 t}

= e^{2 t} + 2 + e^{- 2 t}

\frac{2 ( - 3 x ^{2} + 7 )}{( 3 x ^{2} + 7 ) ^{2}}

f (x) = \frac{8}{( e ^{2 x} + e ^{- 2 x} ) ^{2}}

p o in t s (42 x - 6 y^{2} - ln ∣ x + y ∣)

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s (203 sin (θ), 12 + 123 sin (θ))

What is expand (e^t+e^{-t})^2 ?
The solution to expand (e^t+e^{-t})^2 is e^{2t}+2+e^{-2t}