What is expand-B(x^2-x+1)^2 ?

The solution to expand-B(x^2-x+1)^2 is -Bx^4+2Bx^3-3Bx^2+2Bx-B

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expand-B(x^2-x+1)^2

expand

- B (x^{2} - x + 1)^{2}

- B x^{4} + 2 B x^{3} - 3 B x^{2} + 2 B x - B

Solution steps

- B (x^{2} - x + 1)^{2}

(x^{2} - x + 1)^{2} = x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1

= - B (x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1)

Distribute parentheses

= (- B) x^{4} + (- B) (- 2 x^{3}) + (- B) \cdot 3 x^{2} + (- B) (- 2 x) + (- B) \cdot 1

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= - B x^{4} + 2 B x^{3} - 3 B x^{2} + 2 B x - 1 \cdot B

Multiply:

1 \cdot B = B

= - B x^{4} + 2 B x^{3} - 3 B x^{2} + 2 B x - B

\frac{1}{2} (\frac{1}{2} sin (2 x) - \frac{1}{4} sin (4 x)) + C

e^{A (l n (x) - m)^{2}}

\frac{20 t ( 2 t - 3 )}{13}

\frac{s ^{2} + 1}{s ^{2} ( s ^{2} + 4 )}

\frac{2 ( s - 1 ) e ^{- 2 s}}{s ^{2} - 2 s + 2}

What is expand-B(x^2-x+1)^2 ?
The solution to expand-B(x^2-x+1)^2 is -Bx^4+2Bx^3-3Bx^2+2Bx-B