What is expand sin(2t)U(t-2pi) ?

The solution to expand sin(2t)U(t-2pi) is tUsin(2t)-2piUsin(2t)

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expand sin(2t)U(t-2pi)

expand

sin (2 t) U (t - 2 π)

t U sin (2 t) - 2 π U sin (2 t)

Solution steps

sin (2 t) U (t - 2 π)

= U sin (2 t) (t - 2 π)

Apply the distributive law:

a (b - c) = ab - a c

a = sin (2 t) U, b = t, c = 2 π

= sin (2 t) U t - sin (2 t) U \cdot 2 π

= t U sin (2 t) - 2 π U sin (2 t)

(x + 6) (3 x - 4) d x

(x + y + z = 3) (2)

\frac{2 ( 2 y - 3 )}{y ( y - 3 )}

\frac{1}{2} (6 a + 8)

e^{y} cos (x) + cos (x) + (e^{y} sin (x) + e^{y}) y^{'} (x)

What is expand sin(2t)U(t-2pi) ?
The solution to expand sin(2t)U(t-2pi) is tUsin(2t)-2piUsin(2t)