What is expand 1/((x+2)(x+1)(x-1)(x^2+1)) ?

The solution to expand 1/((x+2)(x+1)(x-1)(x^2+1)) is 1/(x^5-x+2x^4-2)

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expand 1/((x+2)(x+1)(x-1)(x^2+1))

expand

\frac{1}{( x + 2 ) ( x + 1 ) ( x - 1 ) ( x ^{2} + 1 )}

\frac{1}{x ^{5} - x + 2 x ^{4} - 2}

Solution steps

\frac{1}{( x + 2 ) ( x + 1 ) ( x - 1 ) ( x ^{2} + 1 )}

Expand

(x + 2) (x + 1) (x - 1) (x^{2} + 1) : x^{5} - x + 2 x^{4} - 2

= \frac{1}{x ^{5} - x + 2 x ^{4} - 2}

r (cos (θ) + j sin (θ))

(t e^{(- 2 t)} + sin (t) + cos (t))^{2} U (t + 6)

(6 - 8.5 sin (x))^{2}

(3 y^{6} + 4) l e f t (9 y^{12} - 12 y^{6} + 16)

y^{4} (\frac{2 x ^{2}}{y ^{2}} + 1)

What is expand 1/((x+2)(x+1)(x-1)(x^2+1)) ?
The solution to expand 1/((x+2)(x+1)(x-1)(x^2+1)) is 1/(x^5-x+2x^4-2)