What are the solutions to the equation x^2-14x+33=0 ?

The solutions to the equation x^2-14x+33=0 are x=11,x=3

Find the zeros of x^2-14x+33=0

The zeros of x^2-14x+33=0 are x=11,x=3

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x^{2} - 14 x + 33 = 0

x = 11, x = 3

Solution steps

x^{2} - 14 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 33 = 8

x_{1, 2} = \frac{- ( - 14 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8}{2 \cdot 1} : 11

x = \frac{- ( - 14 ) - 8}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 11, x = 3

\frac{29}{4} \cdot 2

2 (m - 1) - 3 (m - 1)^{2} + 2 (m - 1)^{3}

lo g_{2} (5) = x

8 x^{2} + 2 x - 21

d^{2} - 14 d + 45

What are the solutions to the equation x^2-14x+33=0 ?
The solutions to the equation x^2-14x+33=0 are x=11,x=3
Find the zeros of x^2-14x+33=0
The zeros of x^2-14x+33=0 are x=11,x=3