What is expand (3cos(3x)-2sin(3x))^2 ?

The solution to expand (3cos(3x)-2sin(3x))^2 is -5sin^2(3x)-6sin(6x)+9

Popular >

expand (3cos(3x)-2sin(3x))^2

expand

(3 cos (3 x) - 2 sin (3 x))^{2}

- 5 sin^{2} (3 x) - 6 sin (6 x) + 9

Solution steps

(3 cos (3 x) - 2 sin (3 x))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(3 cos (3 x) - 2 sin (3 x))^{2} = (3 cos (3 x))^{2} - 2 \cdot 3 cos (3 x) \cdot 2 sin (3 x) + (2 sin (3 x))^{2}

= (3 cos (3 x))^{2} - 2 \cdot 3 cos (3 x) \cdot 2 sin (3 x) + (2 sin (3 x))^{2}

Simplify

(3 cos (3 x))^{2} - 2 \cdot 3 cos (3 x) \cdot 2 sin (3 x) + (2 sin (3 x))^{2} : - 5 sin^{2} (3 x) - 6 sin (6 x) + 9

= - 5 sin^{2} (3 x) - 6 sin (6 x) + 9

(x + y + z) (x + y + z)

- y (y - e^{2})

(1 - w + w^{2} - 1)^{2}

\frac{( x + 1 ) ( x - 1 ) ( x - 2 ) ( x - 3 )}{6}

2 (x_{1} - x_{2} - x_{3})^{2}

What is expand (3cos(3x)-2sin(3x))^2 ?
The solution to expand (3cos(3x)-2sin(3x))^2 is -5sin^2(3x)-6sin(6x)+9