What is m((r^2)/4+(l^2)/3) ?

The solution to m((r^2)/4+(l^2)/3) is (m(3r^2+4l^2))/(12)

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simplify m((r^2)/4+(l^2)/3)

simplify

m (\frac{r ^{2}}{4} + \frac{l ^{2}}{3})

\frac{m ( 3 r ^{2} + 4 l ^{2} )}{12}

Solution steps

m (\frac{r ^{2}}{4} + \frac{l ^{2}}{3})

Simplify

\frac{r ^{2}}{4} + \frac{l ^{2}}{3} : \frac{3 r ^{2} + 4 l ^{2}}{12}

= m \frac{3 r ^{2} + 4 l ^{2}}{12}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{m ( 3 r ^{2} + 4 l ^{2} )}{12}

\frac{( e ^{z} )}{( z - 1 ) ^{2}}

(\frac{9 + x ^{2}}{5} + \frac{( 6 - x )}{10}) d x

(5 + tan (x)) (5 - tan (x)) + sec^{2} (x)

(32 - 3)^{5}

e^{(1 + i) t}

What is m((r^2)/4+(l^2)/3) ?
The solution to m((r^2)/4+(l^2)/3) is (m(3r^2+4l^2))/(12)