What is expand (pi(9-h^2)(h+3))/3 ?

The solution to expand (pi(9-h^2)(h+3))/3 is -(pih^3)/3-pih^2+3pih+9pi

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expand (pi(9-h^2)(h+3))/3

expand

\frac{π ( 9 - h ^{2} ) ( h + 3 )}{3}

- \frac{π h ^{3}}{3} - π h^{2} + 3 πh + 9 π

Solution steps

\frac{π ( 9 - h ^{2} ) ( h + 3 )}{3}

Expand

π (9 - h^{2}) (h + 3) : 9 πh + 27 π - π h^{3} - 3 π h^{2}

= \frac{9 πh + 27 π - π h ^{3} - 3 π h ^{2}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 πh + 27 π - π h ^{3} - 3 π h ^{2}}{3} = \frac{9 πh}{3} + \frac{27 π}{3} - \frac{π h ^{3}}{3} - \frac{3 π h ^{2}}{3}

= \frac{9 πh}{3} + \frac{27 π}{3} - \frac{π h ^{3}}{3} - \frac{3 π h ^{2}}{3}

Divide the numbers:

\frac{9}{3} = 3

= 3 πh + \frac{27 π}{3} - \frac{π h ^{3}}{3} - \frac{3 π h ^{2}}{3}

Divide the numbers:

\frac{27}{3} = 9

= 3 πh + 9 π - \frac{π h ^{3}}{3} - \frac{3 π h ^{2}}{3}

Divide the numbers:

\frac{3}{3} = 1

= 3 πh + 9 π - \frac{π h ^{3}}{3} - π h^{2}

Rewrite in standard form

= - \frac{π h ^{3}}{3} - π h^{2} + 3 πh + 9 π

\frac{x ^{x^{2}}}{( x + 1 ) ^{(x + 1)^{2}}}

lo g_{10} (10) x^{2}

t (1 - cos (t))

(3 x y - 2 y^{2}) d x + (2 x^{2} - 3 x y) d y

\frac{x + 5}{x ( x + 10 )}

What is expand (pi(9-h^2)(h+3))/3 ?
The solution to expand (pi(9-h^2)(h+3))/3 is -(pih^3)/3-pih^2+3pih+9pi