What is expand 2((x+1)(x+2)(x-1)(x-1)^2) ?

The solution to expand 2((x+1)(x+2)(x-1)(x-1)^2) is 2x^5-8x^3+4x^2+6x-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2((x+1)(x+2)(x-1)(x-1)^2)

expand

2 ((x + 1) (x + 2) (x - 1) (x - 1)^{2})

2 x^{5} - 8 x^{3} + 4 x^{2} + 6 x - 4

Solution steps

2 ((x + 1) (x + 2) (x - 1) (x - 1)^{2})

Remove parentheses:

(a) = a

= 2 (x + 1) (x + 2) (x - 1) (x - 1)^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(x - 1) (x - 1)^{2} = (x - 1)^{1 + 2}

= 2 (x + 1) (x + 2) (x - 1)^{1 + 2}

Add the numbers:

1 + 2 = 3

= 2 (x + 1) (x + 2) (x - 1)^{3}

(x - 1)^{3} = x^{3} - 3 x^{2} + 3 x - 1

= 2 (x + 1) (x + 2) (x^{3} - 3 x^{2} + 3 x - 1)

Expand

(x + 1) (x + 2) : x^{2} + 3 x + 2

= 2 (x^{2} + 3 x + 2) (x^{3} - 3 x^{2} + 3 x - 1)

Expand

(x^{2} + 3 x + 2) (x^{3} - 3 x^{2} + 3 x - 1) : x^{5} - 4 x^{3} + 2 x^{2} + 3 x - 2

= 2 (x^{5} - 4 x^{3} + 2 x^{2} + 3 x - 2)

Expand

2 (x^{5} - 4 x^{3} + 2 x^{2} + 3 x - 2) : 2 x^{5} - 8 x^{3} + 4 x^{2} + 6 x - 4

= 2 x^{5} - 8 x^{3} + 4 x^{2} + 6 x - 4

\frac{t ( t - 20 )}{3 ( t - 4 ) ^{2}}

(x + 1) (x - \frac{7}{9})

\frac{( 1 - y ) ^{3}}{3}

(\frac{b}{a} (x - x_{0}) + y_{0} - c)^{2}

((a \cdot x) - b + ((x - (\frac{l}{2})) \cdot c)) \cdot (x - (\frac{l}{2}))

What is expand 2((x+1)(x+2)(x-1)(x-1)^2) ?
The solution to expand 2((x+1)(x+2)(x-1)(x-1)^2) is 2x^5-8x^3+4x^2+6x-4